New character?
Posted: Wed Dec 12, 2007 3:45 pm
Yay, hooray, the black kitten is back. Good job 
Define Cynical Fan Forums
Fan forum for Azumanga Daioh and Marty (and O&M to a limited extent)
https://definecynical.net/forum/
New character?
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Posted: Wed Dec 12, 2007 5:29 pm
Hit New Post instead of Reply? :X
Posted: Wed Dec 12, 2007 8:04 pm
I hope the black kitty stays.
Posted: Wed Dec 12, 2007 8:50 pm
DCS very well might develop him. But he could turn into another Locke, just sort of discussed from time to time but not too important anymore.
Posted: Wed Dec 12, 2007 9:49 pm
Ya true. Hey, is he the same one from before when Millie was trying to make Ozy have bad luck?
Posted: Wed Dec 12, 2007 10:36 pm
I'm not sure if Dhokarena was talking about Stevie or Mu-nan.
Posted: Wed Dec 12, 2007 10:49 pm
Actually, I would say that for both.
Posted: Wed Dec 12, 2007 11:08 pm
Relax, 71% of paupal's posts are new topics.Hit New Post instead of Reply? :X
Posted: Wed Dec 12, 2007 11:30 pm
black kitty might become lyke Emily teh skunk
Posted: Thu Dec 13, 2007 2:33 am
Most probaly.Ya true. Hey, is he the same one from before when Millie was trying to make Ozy have bad luck?
Posted: Thu Dec 13, 2007 2:51 am
Yep.Most probaly.Ya true. Hey, is he the same one from before when Millie was trying to make Ozy have bad luck?
Posted: Thu Dec 13, 2007 6:01 am
Don't worry if you make a mistake like that you don't have to t ype stuff in the box you can just close the windown.Hit New Post instead of Reply? :X
Posted: Thu Dec 13, 2007 11:11 am
Also moved this topic to the Ozy and Millie forum, Current Strips are for discussing the comics.
Posted: Thu Dec 13, 2007 12:53 pm
The black cat is Stevie. We have seen him before. I think he even wore the same shirt.
Also, the little puzzle in Extreme-Speed's signature:
To make this sentence true, the number of times we see 1 is _____, 2 is _____, 3 is _____, 4 is _____, and 5 is _____.
It can be answered with "one, one, one, one, and one," because if you spell it out, you only see "1" one time, "2" one time, "3" one time, "4" one time, and "5" one time. If you try to use the actual digits, it gets tricky.
Also, the little puzzle in Extreme-Speed's signature:
To make this sentence true, the number of times we see 1 is _____, 2 is _____, 3 is _____, 4 is _____, and 5 is _____.
It can be answered with "one, one, one, one, and one," because if you spell it out, you only see "1" one time, "2" one time, "3" one time, "4" one time, and "5" one time. If you try to use the actual digits, it gets tricky.
Posted: Thu Dec 13, 2007 1:16 pm
3, 2, 3, 1, 1.Also, the little puzzle in Extreme-Speed's signature:
To make this sentence true, the number of times we see 1 is _____, 2 is _____, 3 is _____, 4 is _____, and 5 is _____.
It can be answered with "one, one, one, one, and one," because if you spell it out, you only see "1" one time, "2" one time, "3" one time, "4" one time, and "5" one time. If you try to use the actual digits, it gets tricky.
Wrote a dumb brute-force Perl script to solve it.Code: Select all
my $n = 6;
for my $one (1..$n) {
for my $two (1..$n) {
for my $three (1..$n) {
for my $four (1..$n) {
for my $five (1..$n) {
my @t = (0, 1, 1, 1, 1, 1);
$t[$_] += 1 for (0, $one, $two, $three, $four, $five);
if (($t[1] == $one)
&& ($t[2] == $two)
&& ($t[3] == $three)
&& ($t[4] == $four)
&& ($t[5] == $five)) {
print "$one, $two, $three, $four, $five\n";
exit(0);
} # if
} # for
} # for
} # for
} # for
} # for
print "Unsolvable for n(1,$n)\n";
exit(1);